Looking for easier ways to find privkey

Hey everyone. Does anyone have tips on how to find the private key more easily on curve with k not equal to 7? Like what if k equals 1, 2, or even n? Thanks a lot!

Finding a private key of a given address is like finding an atom in the universe by which I mean it's impossible. If it is possible, Bitcoin blockchain is useless and very risky to use, hence I believe nobody will have belief in Bitcoin and use it to store money. Combinations of Bitcoin private keys is 1077 and the universe has 1080 atoms. You can not find an atom in the universe so neither find a Bitcoin private key to hijack a wallet of someone else.

Idea from this code of Krashfire, but hi not on connection now... https://github.com/KrashKrash/Twist-Attack-Sub-Group-Attack Looks like hi find something for change points order

Krashfire finds something what looks like a privatekeys in subgroups, but code need to be  midified and verified. Output reult of his sceypt: (privkey,order), (privkey,order).... Partial private keys for {name} [(0, 3), (6, 13), (1502, 3319), (8892, 22639)] ------------------------------------------------- so for reconstruct final privkey need additional work, but, I think he is MAKE INTERESTING SCRYPT,I try to do the same with subgroups, but I take any privkeys..... Many thanks Krashfire for his scrypt So, have someone any ideas how to modify Krashfire scrypt for take result ?

scrypt output: Final private key found using CRT: 26824948988 xman@localhost:~$

We know you and Krashfire want to steal some good money but this won't help you. Why? Because you take X of a valid point on secp256k1 and use it to get Y on a different curve (twisted or not). This new point represents a totally different privatekey on this new curve. Whatever those fancy algorithms, that you and me don't understand, spit out, won't give you and Krashfire anything to steal bitcoins. Krashfire uses this method to create some mysterious uncertainty for some reason (likely malicious).

eustion for Krash points is: Уpaвнeниe эллиптичecкoй кpивoй, пpoxoдящeй чepeз тoчки P и Q: Elliptic Curve defined by y^2 = x^3 + 5*x - 496083217762525229200448345979197619411513160320101887952589222190456726748741 over Rational Field H you can try fund eqation of curve yoursek : replace Q P coirdinates,tgey mast was from one curve